(X-1)(x+5)=x^2+4x-2=

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Solution for (X-1)(x+5)=x^2+4x-2= equation: 



(X-1)(X+5)=X^2+4X-2=

We move all terms to the left:

(X-1)(X+5)-(X^2+4X-2)=0

We get rid of parentheses

-X^2+(X-1)(X+5)-4X+2=0

We multiply parentheses ..

-X^2+(+X^2+5X-1X-5)-4X+2=0

We add all the numbers together, and all the variables

-1X^2+(+X^2+5X-1X-5)-4X+2=0

We get rid of parentheses

-1X^2+X^2+5X-1X-4X-5+2=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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